- Joined
- Jun 9, 2010
- Messages
- 818
If I've got 3 cards and no set then I've got a 66.6(recurring)% chance of my next card giving me a set, right - 2 out of the 3 possible colours will give me a set - however this doesn't take into account the chances of my first 3 cards being a set before I turn over my 4th, which I reckon is 33.3(recurring)%. So. Clearly the chances of having a set with 4 cards is 66.6(recurring)%+33.3(recurring)% or 99.9(recurring)%.
ohhh... i see you borrowed a page from the same logic recipe book that many people use for dice odds...
Except that you added 22 pinches of sarcasm, lol...
And just to add my thoughts into the prior discussion...
You were 10 to 1 when the losing streak began...
but we see HOT dice the 2 rolls prior, which shows you had 10 attacking 5 (cannot see the rolls prior to that)
So with 10 vs 5, the defender has a 13% chance of staying alive
ODDS OF OCCURRING : 1 in 8
But let's focus on the more interesting FAIL segment of 10 vs 1
With that 10 v 1 segment, the defender has only a .013% chance of staying alive
ODDS OF OCCURRING : 1 in ~7,700
So what if there had been 1 more attacker,
then with a roughly 1 in 3 chance of the defender winning again,
we would be even more impressed as the odds would then be 1 in ~23,000...
That is with just ONE more roll that has ONLY AND ALWAYS a 1 in 3 chance... Think about it :hmmmm:
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